X^2+y^2=26.01

Solution for X^2+y^2=26.01 equation:

X^2+X^2=26.01

We move all terms to the left:

X^2+X^2-(26.01)=0

We add all the numbers together, and all the variables

2X^2-26.01=0

a = 2; b = 0; c = -26.01;
Δ = b2-4ac
Δ = 02-4·2·(-26.01)
Δ = 208.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{208.08}}{2*2}=\frac{0-\sqrt{208.08}}{4}
=-\frac{\sqrt{}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{208.08}}{2*2}=\frac{0+\sqrt{208.08}}{4}
=\frac{\sqrt{}}{4}
$